Your code would work with the following corrections:
dim varia[]
varia[1]=a1
varia[2]=a2
varia[3]=a3
varia[4]=a4
varia[5]=a5
Quotation marks not needed.
if varia[LIT][i][/LIT]=1 then
parameters set with values{2} can be used as numbers.
Péter Baksa
Library Platform, Software Engineer
GRAPHISOFT SE
