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[Szabadi Gergely]

by flags I ment unID

G. Szabadi

[Szabadi Gergely]

Thanks again! When I add flags for the hotspot, in section view the scaling follows the object, BUT If I have an object, where I use macro object more then one, I have problem with the unique flags because they have to be unique, but it is defined the same way.
Any solution?

Thx

G. Szabadi

[Szabadi Gergely]

Thank you!

G. Szabadi

[Szabadi Gergely]

I had found an other problem with it. This is nice, working fine, create 5 block, but if a3=2 still creat 5 block instead of skipping the 3th one

parameters a1, a2, a3, a4, a5

!MASTER SCRIPT

dim 	parama[2][5]
	parama[1][1]=1
	parama[1][2]=2
	parama[1][3]=3
	parama[1][4]=4
	parama[1][5]=5
	parama[2][1]='opt1'
	parama[2][2]='opt2'
	parama[2][3]='opt3'
	parama[2][4]='opt4'
	parama[2][5]='opt5'

dim varia[]
    varia[1]=a1
    varia[2]=a2
    varia[3]=a3
    varia[4]=a4
    varia[5]=a5

!PARAMETERS SCRIPT

for k=1 to 5
values{2} "a"+str(k,1,0) parama[1], parama[2]
next k

!3D SCRIPT

for i=1 to 5
if varia[ i ]=1 then
addx (i-1)*.5
block 1, 1, 1
del 1
endif
next i

G. Szabadi

[Szabadi Gergely]

Again, thanks. Huge help! Bu I don’t understand why is this working after if command and why it is not working with parameter command.

if varia[ i ]= 1 then ! works fine
parameters varia2[ i ]=2 ! doesn’t work

G. Szabadi

[Szabadi Gergely]

Thank you very much!!!!!!!!!!!!!

G. Szabadi

[Szabadi Gergely]

Thanks for the answer!
I tried to create loop with arrays, but still now working. I don’t get error massage, the script is good, but not working. Does anybody has an idea, why?

parameters a1, a2, a3, a4, a5

!MASTER SCRIPT

dim 	parama[2][5]
	parama[1][1]=1
	parama[1][2]=2
	parama[1][3]=3
	parama[1][4]=4
	parama[1][5]=5
	parama[2][1]='opt1'
	parama[2][2]='opt2'
	parama[2][3]='opt3'
	parama[2][4]='opt4'
	parama[2][5]='opt5'

dim varia[]
    varia[1]='a1'
    varia[2]='a2'
    varia[3]='a3'
    varia[4]='a4'
    varia[5]='a5'

!PARAMETERS SCRIPT

for k=1 to 5
values{2} "a"+str(k,1,0) parama[1], parama[2]
next k

!3D SCRIPT

for i=1 to 5
if varia(i)='opt1' then     !I have error to submit here the right type of bracket 
addx (i-1)*.5
block 1, 1, 1
del 1
endif
next i

G. Szabadi

[Szabadi Gergely]

Thank you very much for your answer, so it seems that I can’t concanenate strings to refer a variable name. Does anybody know how to shorten these:

variables: a1, a2, a3, a4, a5

for i=1 to 5
values{2} "a"+str(i,1,0) 1, 'opt1', 2, 'opt2'
next i

if a1=1 then
...
endif

if a2=1 then
....
endif

etc.

if a string can equal to a string, than why is this not working?

for i=1 to 4
if "a"+str(i,1,0)='opt1' then
....
endif
next i

G. Szabadi

[Szabadi Gergely]

Thank you very much it works well!

Can you help me script this parameter if I want to use it in an “if”- type control statement?

for i = 1 to 10
if "param"+STR(i,1,0) = 2 then
....
else
endif
next i

I get error massage with and without the quotation marks too. I can’t figure out why

G. Szabadi

[Szabadi Gergely]

Thank you, for your answer

it is working fine (I don’t have so many parameters to reach the limit), but can you tell me any way, except copy the script, to add these parameters one kind of values?

I have:

param1
param2
param3
etc.

and I want to write same values for all of them, but it seems that this is not the best solution:

values{2} "param1" 1, 'opt1', 2, 'opt2 etc...
values{2} "param2" 1, 'opt1', 2, 'opt2 etc...
values{2} "param3" 1, 'opt1', 2, 'opt2 etc...

can I loop this somehow?

G. Szabadi

[Author]

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